Уточнение вопроса
Help pls
 - log_{4}(x) + frac{7}{6} = 0 "log_{x}(2) - log_{4}(x) + frac{7}{6} = 0")
Подробное решение
log(x)2-log(4)x+7/6=0
1)x>0;x≠1
2)1/log(2)x-1/2*log(2)x+7/6=0
log(2)x=t
(1/t)-t/2+7/6=0
6-3t²+7t=0
3t²-7t-6=0
D=49+72=121=11²
t=(7±11)/6
t1=3;t2=-4/6=-2/3
log(2)x=3
x=2³=8
log(2)x=-2/3
x=(1/2)²/³